6y^2+54y+48=0

Solution for 6y^2+54y+48=0 equation:

6y^2+54y+48=0

a = 6; b = 54; c = +48;
Δ = b2-4ac
Δ = 542-4·6·48
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-42}{2*6}=\frac{-96}{12}
=-8
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+42}{2*6}=\frac{-12}{12}
=-1
$